Radicals in Fractions - Rationalizing Denominators w/ Complex Conjugates

Rationalize the denominators in the following fractions:

1.  $\dfrac{3+\sqrt{17}}{2-3\sqrt{17}}\times \dfrac{2+3\sqrt{17}}{2+3\sqrt{17}}=\dfrac{6+2\sqrt{17}+9\sqrt{17}+3(17)}{4-9(17)}=\dfrac{57+11\sqrt{17}}{-149}$
2. $\dfrac{11+\sqrt{7}}{\sqrt{2}+\sqrt{5}}\times \dfrac{2-\sqrt{5}}{2-\sqrt{5}}=\dfrac{11\sqrt{2}+\sqrt{14}-11\sqrt{5}-\sqrt{35}}{2-5}=\dfrac{11\sqrt{2}+\sqrt{14}-11\sqrt{5}-\sqrt{35}}{-3}$
3. $\dfrac{4+\sqrt{10}}{\sqrt{2}+\sqrt{5}}\times \dfrac{2-\sqrt{5}}{2-\sqrt{5}}=\dfrac{4\sqrt{2}+\sqrt{20}-4\sqrt{5}-\sqrt{50}}{2-5}=\dfrac{-2\sqrt{5}-\sqrt{2}}{-3}=\dfrac{2\sqrt{5}+\sqrt{2}}{3}$
4. $\dfrac{6}{3+4i}\times \dfrac{3-4i}{3-4i}=\dfrac{18-24i}{25}=\dfrac{6(3-4i)}{25}$
5. $\dfrac{7+5i}{2-2i}\times \dfrac{2+2i}{2+2i}=\dfrac{14+14i+10i-10}{4+4}=\dfrac{4+24i}{8}=\dfrac{1+6i}{2}$
6. $\dfrac{9-9i}{9+9i}\times \dfrac{9-9i}{9-9i}=\dfrac{81-81i-81i-81}{81+81}=\dfrac{-168i)(168}=-i$
7. $\dfrac{3+\sqrt[3]{4}}{\sqrt[3]{5}}\times \dfrac{5^\frac{2}{3}}{5^\frac{2}{3}}=\dfrac{3\sqrt[3]{25}+\sqrt[3]{100}}{5}$
8. $\dfrac{6-\sqrt{35}}{\sqrt{5}-\sqrt{7}} \times \dfrac{\sqrt{5}+\sqrt{7}}{\sqrt{5}+\sqrt{7}}=\dfrac{6\sqrt{5}+6\sqrt{7}-\sqrt{175}-\sqrt{245}}{5-7}=\dfrac{6\sqrt{5}+6\sqrt{7}-5\sqrt{7}-7\sqrt{5}}{-2}=\dfrac{\sqrt{7}-\sqrt{5}}{-2}$
9. $\dfrac{5-2i}{3+3i}\times \dfrac{3-3i}{3-3i}=\dfrac{15-15i-6i-6}{9+9}=\dfrac{9-21i}{18}=\dfrac{3-7i}{6}$
10. $\dfrac{2+2i}{3i}\times \dfrac{3i}{3i}=\dfrac{-6+6i}{-9}=\dfrac{2-2i}{3}$